Since the sine function can only have outputs from 1 to 1, its inverse can only accept inputs from 1 to 1 The domain of inverse sine is 1 to 1 However, the most common example of a limited domain is probably the divide by zero issue When asked to find the domain of a function, start with the easy stuff first look for any values thatYou can put this solution on YOUR website!1 2 A B Now the areas required are obviously the area A between x = 0 and x = 1, and the area B between x = 1 and x = 2 But there is a marked difference between these two areas in terms of their position The area A is above the xaxis, whereas the area B is below it In previous units
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Then add the square of 1 to both sides of the equation This step makes the left hand side of the equation a perfect square x^{2}2x1=y61 Square 1 x^{2}2x1=y5 Add y6 to 1 \left(x1\right)^{2}=y5 Factor x^{2}2x1 In general, when x^{2}bxc is a perfect square, it can always be factored as \left(x\frac{b}{2}\right)^{2}2x2y=4 Geometric figure Straight Line Slope = 1 xintercept = 2/1 = 0000 yintercept = 2/1 = 0000 Rearrange Rearrange the equation by subtracting what is to the right of theSimilarly, since f(1) = 4 < 0 and f(2) = 5 > 0, we conclude by the Intermediate Value Theorem that f has at least one zero in the interval (1;2) Finally, since the intervals (0;1) and (1;2) are disjoint, f has at least two zeros 12 Find the derivative of y = 1 p x 1 using the de nition of the derivative Solution y0= lim h!0 p 1
Solve your math problems using our free math solver with stepbystep solutions Our math solver supports basic math, prealgebra, algebra, trigonometry, calculus and moreY=x^22x4 graphing this equation we have no x intercepts solving this equation by setting y=0 & using the quadratic equation we get irrational values which supports the no x intercept graphY=2x4 Geometric figure Straight Line Slope = 4000/00 = 00 xintercept = 4/2 = 2/1 = 0000 yintercept = 4/1 = Rearrange Rearrange the equation by subtracting
Free equations calculator solve linear, quadratic, polynomial, radical, exponential and logarithmic equations with all the steps Type in any equation to get the solution, steps and graphApr 24, 14 · y=2x4 and y=x1 this gives us, by replacing y in the first equation with x1 = 2x4 subtract the left side x from the right side gives us 1 = x 4 subtracting known values x = 3 verfy the results gives us 2 (3) 4 = y 2 = y also 3 1 = y 2 = y so you wind up with x = 3 and y = 2F(3) = 1 − 3 3 2 = 1 − 3 9 = 7 Evaluate For a Given Expression Evaluating can also mean replacing with an expression (such as 3m1 or v 2) Let us evaluate the function for x=1/r f(1/r) = 1 − (1/r) (1/r) 2 Or evaluate the function for x = a−4
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Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutorY = 2 x 4 − x 2 ⇒ d x d y = 8 x 3 − 2 x = 2 x (4 x 2 − 1) = 0, for extrema ⇒ x = ± 2 1 Thus required area = − 2 ∫ 0 1 / 2 ( 2 x 4 − x 2 ) d x = 1 2 0 7Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with stepbystep explanations, just like a math tutor
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